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2.4 puzzle time where do young tigers swim? write the letter of each an…

Question

2.4 puzzle time
where do young tigers swim?
write the letter of each answer in the box containing the exercise number.
solve the inequality.

  1. (4x - 7 < 9)
  2. (-11>10 - 7x)
  3. (\frac{x}{6}+5 > 8)
  4. (\frac{x}{2}+12geq14)
  5. (6x - 23>25)
  6. (6-\frac{x}{5}geq - 2)
  7. (3geq - 3(x - 13))
  8. (16 - 4x>9 - 5x)
  9. (2x + 7leq2x + 8)
  10. (-6(x - 1)<-14(x - 5))
  11. (12x + 4x-11geq16x + 17)
  12. (3(1 - x)+10xleq9(x - 2)+7)
  13. the students in charge of the class booth at a carnival want to make a profit of at least $65 by selling items. they spent $55 for the materials to make the items. they will sell each item for $3. find the possible values of x, the number of items the students need to sell to reach their goal.
  14. a triangle has a base of 14 centimeters and a height of ((3x - 4)) centimeters. the area of the triangle is greater than 56 centimeters. find the possible values of x.

answers
n. all real numbers
k. (xgeq7)
r. (x < 8)
e. (x>3)
o. (x < 4)
l. (x>8)
o. (xgeq40)
y. (xleq - 4)
t. (x>4)
l. (x>-7)
t. no solution
h. (xgeq12)
i. (xleq40)
t. (x>18)

Explanation:

Step1: Solve 4x - 7 < 9

Add 7 to both sides: 4x<9 + 7, 4x<16. Then divide both sides by 4, x < 4. The answer is O.

Step2: Solve - 11>10 - 7x

Add 7x to both sides: 7x-11>10. Add 11 to both sides: 7x>10 + 11, 7x>21. Divide both sides by 7, x > 3. The answer is E.

Step3: Solve $\frac{x}{6}+5>8$

Subtract 5 from both sides: $\frac{x}{6}>8 - 5$, $\frac{x}{6}>3$. Multiply both sides by 6, x>18. The answer is T.

Step4: Solve $\frac{x}{2}+12\geq14$

Subtract 12 from both sides: $\frac{x}{2}\geq14 - 12$, $\frac{x}{2}\geq2$. Multiply both sides by 2, x≥4. There is no exact match in the given answers for this one.

Step5: Solve 6x - 23>25

Add 23 to both sides: 6x>25 + 23, 6x>48. Divide both sides by 6, x>8. The answer is L.

Step6: Solve 6 - $\frac{x}{5}\geq - 2$

Subtract 6 from both sides: -$\frac{x}{5}\geq - 2-6$, -$\frac{x}{5}\geq - 8$. Multiply both sides by - 5 (and reverse the inequality sign), x≤40. The answer is I.

Step7: Solve 3≥ - 3(x - 13)

Divide both sides by - 3 (and reverse the inequality sign): - 1≤x - 13. Add 13 to both sides, x≥12. The answer is H.

Step8: Solve 16 - 4x>9 - 5x

Add 5x to both sides: 16 + x>9. Subtract 16 from both sides, x>-7. The answer is L.

Step9: Solve 2x + 7≤2x + 8

Subtract 2x from both sides: 7≤8. This is true for all real - numbers. The answer is N.

Step10: Solve - 6(x - 1)< - 14(x - 5)

Expand: - 6x+6<-14x + 70. Add 14x to both sides: 8x+6<70. Subtract 6 from both sides: 8x<64. Divide both sides by 8, x<8. The answer is R.

Step11: Solve 12x + 4x - 11≥16x + 17

Combine like terms: 16x-11≥16x + 17. Subtract 16x from both sides: - 11≥17, which is false. So there is no solution. The answer is T.

Step12: Solve 3(1 - x)+10x≤9(x - 2)+7

Expand: 3-3x + 10x≤9x-18 + 7. Combine like terms: 3 + 7x≤9x-11. Subtract 7x from both sides: 3≤2x-11. Add 11 to both sides: 14≤2x. Divide both sides by 2, x≥7. The answer is K.

Step13: Set up the inequality for the profit problem

The cost is 55, and they sell each item for 3. They want a profit of at least 65. So 3x-55≥65. Add 55 to both sides: 3x≥65 + 55, 3x≥120. Divide both sides by 3, x≥40. The answer is O.

Step14: Set up the inequality for the triangle area problem

The area of a triangle A=$\frac{1}{2}bh$. Here, b = 14 and h=(3x - 4), and A>56. So $\frac{1}{2}\times14\times(3x - 4)>56$. Simplify: 7(3x - 4)>56. Divide both sides by 7: 3x-4>8. Add 4 to both sides: 3x>12. Divide both sides by 3, x>4. The answer is T.

Answer:

  1. O. x < 4
  2. E. x > 3
  3. T. x > 18
  4. (No exact match)
  5. L. x > 8
  6. I. x ≤ 40
  7. H. x ≥ 12
  8. L. x > - 7
  9. N. all real numbers
  10. R. x < 8
  11. T. no solution
  12. K. x ≥ 7
  13. O. x ≥ 40
  14. T. x > 4