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quadrilateral kite with vertices k(0, -2), i(1, 2), t(7, 5), and e(4, -…

Question

quadrilateral kite with vertices k(0, -2), i(1, 2), t(7, 5), and e(4, -1) is a

  • (-2)^2+(1 - 0)^2 = \sqrt{17}, ke =

17
137
square root of 17
square root of 137
reset

Explanation:

Step1: Recall distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. For points $K(0,-2)$ and $E(4,-1)$, we have $x_1 = 0,y_1=-2,x_2 = 4,y_2=-1$.

Step2: Substitute values into formula

$KE=\sqrt{(4 - 0)^2+(-1-(-2))^2}=\sqrt{4^2+( - 1 + 2)^2}=\sqrt{16 + 1}=\sqrt{17}$.

Answer:

square root of 17