Question

question 8 (01.03 mc) the perimeter of a rectangle can be found using the equation p = 2l + 2w, where p is the perimeter, l is the length, and w is the width of the rectangle. can the perimeter of the rectangle be 64 units when its width is 11 units and its length is 20 units? no, if the length is 20 and the width is 11, the perimeter is p = 20 + 22 = 42, not 64. no, if the length is 20 and the width is 11, the perimeter is p = 40 + 22 = 62, not 64. yes, if the perimeter is 64 units and the width is 11 units, then p + w is greater than 40. yes, if the perimeter is 64 units and the width is 11 units, then p + w is less than 40.

Explanation:

Step1: Recall perimeter formula

The formula for the perimeter of a rectangle is $P = 2L+2W$.

Step2: Substitute given values

Given $L = 20$ and $W = 11$. Substitute into the formula: $P=2\times20 + 2\times11$.

Step3: Calculate

First, calculate $2\times20=40$ and $2\times11 = 22$. Then $P=40 + 22=62$.

Answer:

No, if the length is 20 and the width is 11, the perimeter is $P=40 + 22=62$, not 64.