Question

question 5 of 10
this equation will be in standard form if you subtract 2x^{2} from both sides and add 7x to both sides.
5x^{2}+3x - 8 = 2x^{2}-7x
a. false
b. true

Explanation:

Step1: Perform subtraction

Subtract $2x^{2}$ from both sides of $5x^{2}+3x - 8=2x^{2}-7x$.
Left - hand side: $(5x^{2}+3x - 8)-2x^{2}=3x^{2}+3x - 8$.
Right - hand side: $(2x^{2}-7x)-2x^{2}=-7x$.
The equation becomes $3x^{2}+3x - 8=-7x$.

Step2: Perform addition

Add $7x$ to both sides.
Left - hand side: $3x^{2}+3x - 8+7x=3x^{2}+10x - 8$.
Right - hand side: $-7x + 7x=0$.
The resulting equation is $3x^{2}+10x - 8 = 0$, which is in the standard quadratic form $ax^{2}+bx + c=0$ ($a = 3$, $b = 10$, $c=-8$).

Answer:

B. True