Question

question 2 of 10 jake drags a sled of mass 10 kg across the snow. the sled is attached to a rope that he pulls with a force of 30 n at an angle of 25°. if there is no friction, what is the normal force acting on the sled? a. 85.3 n b. 70.8 n c. 12.7 n d. 27.2 n

Explanation:

Step1: Calculate the weight of the sled

The weight of the sled $W = mg$, where $m = 10$ kg and $g=9.8$ m/s². So $W=10\times9.8 = 98$ N.

Step2: Calculate the vertical - component of the pulling force

The pulling force is $F = 30$ N and the angle is $\theta = 25^{\circ}$. The vertical - component of the pulling force $F_y=F\sin\theta$. So $F_y = 30\times\sin(25^{\circ})\approx30\times0.4226 = 12.678$ N.

Step3: Find the normal force

In the vertical direction, the net force is zero. Let the normal force be $N$. Then $N + F_y=W$. So $N=W - F_y$. Substituting the values of $W$ and $F_y$, we get $N = 98-12.678=85.322\approx85.3$ N.

Answer:

A. 85.3 N