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question 10 0.5 pts write the equation of the line that goes through th…

Question

question 10
0.5 pts
write the equation of the line that goes through the point (2,-3) and has a slope of -2.

  • ( y - 2 = -2(x + 3) )
  • ( y - 3 = -2(x + 2) )
  • ( y + 3 = -2(x - 2) )
  • ( y + 2 = -2(x - 3) )

Explanation:

Step1: Recall point - slope form

The point - slope form of a line is given by $y - y_1=m(x - x_1)$, where $(x_1,y_1)$ is a point on the line and $m$ is the slope of the line.

Step2: Identify $x_1,y_1$ and $m$

We are given the point $(2,-3)$, so $x_1 = 2$ and $y_1=-3$. The slope $m=-2$.

Step3: Substitute into point - slope form

Substitute $x_1 = 2$, $y_1=-3$ and $m = - 2$ into the point - slope form $y - y_1=m(x - x_1)$.
We get $y-(-3)=-2(x - 2)$, which simplifies to $y + 3=-2(x - 2)$.

Answer:

$y + 3=-2(x - 2)$ (corresponding to the option: $y + 3=-2(x - 2)$)