Question

question 7 of 10, step 1 of 1
a $6\frac{6}{7}$ inch pipe is to be shortened to $1\frac{1}{5}$ inch. how much must be removed?
answer

Explanation:

Step1: Set up subtraction

$\frac{6}{7} - \frac{1}{5}$

Step2: Find common denominator

The least common denominator of 7 and 5 is 35.
$\frac{6\times5}{7\times5} - \frac{1\times7}{5\times7} = \frac{30}{35} - \frac{7}{35}$

Step3: Subtract fractions

$\frac{30 - 7}{35} = \frac{23}{35}$

Answer:

$\frac{23}{35}$ inch