Question

question 11 of 45
which of the following inequalities describes the solution set for $3x - 5 < 2x + 1$
a $x < -4$
b $x > \frac{-4}{5}$
c $x < \frac{6}{5}$
d $x < 6$

Explanation:

Step1: Isolate x terms

Subtract $2x$ from both sides.
$3x - 2x - 5 < 2x - 2x + 1$
Simplify to get: $x - 5 < 1$

Step2: Isolate x

Add 5 to both sides.
$x - 5 + 5 < 1 + 5$
Simplify to get: $x < 6$

Answer:

D. $x < 6$