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question 14 of 28 alan rented a truck for one day. there was a base fee…

Question

question 14 of 28
alan rented a truck for one day. there was a base fee of $18.95, and there was an additional charge of $0.88 for each mile driven. alan had to pay $135.99 when he returned the truck. for how many miles did he drive the truck?
square miles
question 15 of 28
solve for x.
-\frac{3}{5}x - 4=\frac{6}{5}x+\frac{1}{3}
simplify your answer as much as possible.

Explanation:

(Question 14):

Step1: Define total cost equation

Let $m$ = miles driven. Total cost = base fee + per-mile cost.
$\$135.99 = \$18.95 + 0.88m$

Step2: Isolate the per-mile term

Subtract base fee from both sides.
$135.99 - 18.95 = 0.88m$
$117.04 = 0.88m$

Step3: Solve for miles

Divide both sides by 0.88.
$m = \frac{117.04}{0.88}$

(Question 15):

Step1: Combine like terms (x terms)

Add $\frac{3}{5}x$ to both sides.
$-4 = \frac{6}{5}x + \frac{3}{5}x + \frac{1}{3}$
$-4 = \frac{9}{5}x + \frac{1}{3}$

Step2: Isolate the x term

Subtract $\frac{1}{3}$ from both sides.
$-4 - \frac{1}{3} = \frac{9}{5}x$
$-\frac{13}{3} = \frac{9}{5}x$

Step3: Solve for x

Multiply both sides by $\frac{5}{9}$.
$x = -\frac{13}{3} \times \frac{5}{9}$

Answer:

Question 14: 133 miles
Question 15: $-\frac{65}{27}$