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question 19 (mandatory) (1 point) if 3^{2x - 3}=27, then x is equal to a) 6 b) 3 c) 4 d) 2
Step1: Rewrite 27 as a power of 3
Since \(27 = 3^3\), the equation \(3^{2x - 3}=27\) becomes \(3^{2x - 3}=3^3\).
Step2: Equate the exponents
If \(a^m=a^n\), then \(m = n\). So, \(2x-3 = 3\).
Step3: Solve for x
Add 3 to both sides: \(2x=3 + 3=6\). Then divide both sides by 2: \(x=\frac{6}{2}=3\).
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b) 3