Question

question 20
1 pts
what type of radiation is present in the following nuclear decay reaction: (^{210}_{85}at
ightarrow ^{0}_{- 1}e+^{210}_{86}rn)
alpha
beta
gamma

Explanation:

In beta - decay, a neutron in the nucleus is converted into a proton, an electron (beta - particle), and an antineutrino. The electron is emitted from the nucleus. In the given reaction $^{210}_{85}At
ightarrow ^{0}_{ - 1}e+^{210}_{86}Rn$, the atomic number of the parent nucleus ($At$) increases by 1 and a particle with a mass number of 0 and charge of - 1 (an electron) is emitted, which is characteristic of beta - decay. Alpha - decay involves the emission of a $^{4}_{2}He$ nucleus, and gamma - decay involves the emission of high - energy photons without a change in mass number or atomic number.

Answer:

B. Beta