Question

question 22 of 25 given any triangle abc with corresponding side lengths a, b, and c, the law of cosines states. a. b² = a² - c² - 2bccos(b) b. b² = a² - c² - 2bccos(c) c. b² = a² + c² - 2bccos(a) d. b² = a² + c² - 2accos(b)

Explanation:

Step1: Recall law of cosines formula

The law of cosines for side \(b\) in \(\triangle ABC\) is \(b^{2}=a^{2}+c^{2}-2ac\cos(B)\). This formula relates the lengths of the sides of a triangle to the cosine of one of its angles.

Answer:

D. \(b^{2}=a^{2}+c^{2}-2ac\cos(B)\)