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Question
question 23, *7.5. solve the equation. log 16(4x - 1) = 1/4 x = (simplify your answer.)
Step1: Convert to exponential form
By the definition of logarithms, if $\log_{a}b = c$, then $b=a^{c}$. So, $4x - 1=16^{\frac{1}{4}}$.
Step2: Calculate $16^{\frac{1}{4}}$
We know that $16 = 2^4$, so $16^{\frac{1}{4}}=(2^4)^{\frac{1}{4}} = 2$. Then the equation becomes $4x - 1=2$.
Step3: Solve for $x$
Add 1 to both sides: $4x=2 + 1=3$. Then divide both sides by 4, we get $x=\frac{3}{4}$.
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$\frac{3}{4}$