Question

question 8 | bcpss_course3_unit6
this question has two parts. first, answer part a. then, answer part b.
part a
consider the value $sqrt{10}$.
between what two integers does $sqrt{10}$ fall? enter the answer.
between $square$ and $square$
part b
estimate $sqrt{10}$ to the nearest integer. enter the answer.
$square$

Explanation:

Step1: Find nearby perfect squares

Calculate squares of consecutive integers:
$3^2 = 9$, $4^2 = 16$

Step2: Compare to $\sqrt{10}$

Since $9 < 10 < 16$, take square roots: $\sqrt{9} < \sqrt{10} < \sqrt{16}$, so $3 < \sqrt{10} < 4$.

Step3: Estimate to nearest integer

$\sqrt{10} \approx 3.16$, which is closer to 3 than 4.

Answer:

Part A: between 3 and 4
Part B: 3