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an architect is designing a new building. he makes a model of the building such that the area of the rectangular base is (12x^2 - 11x - 5) and the length is (3x + 1).
what is the width of the model in terms of (x)?
Step1: Recall rectangle area formula
Area = Length × Width, so Width = $\frac{\text{Area}}{\text{Length}}$
Step2: Substitute given expressions
Width = $\frac{12x^2 - 11x - 5}{3x + 1}$
Step3: Factor the quadratic numerator
$12x^2 - 11x - 5 = (3x + 1)(4x - 5)$
Step4: Cancel common factors
Width = $\frac{(3x + 1)(4x - 5)}{3x + 1} = 4x - 5$ (for $3x+1
eq0$)
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$4x - 5$