Question

question
$f(x) = \

$$\begin{cases} -(x + 6)^2 & \\text{for} & x \ eq -5 \\\\ -3 & \\text{for} & x = -5 \\end{cases}$$

$
find $f(-5)$
answer attempt 1 out of 2
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Explanation:

Step1: Identify the case for \( x = -5 \)

The piecewise function \( f(x) \) is defined as \( f(x) = -3 \) when \( x = -5 \).

Step2: Determine \( f(-5) \)

Since we are finding \( f(-5) \), we use the part of the piecewise function where \( x = -5 \), so \( f(-5) = -3 \).

Answer:

\( -3 \)