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Question
question
factor.
$x^2 - 13x + 30$
Step1: Find two numbers
We need two numbers that multiply to \(30\) (the constant term) and add up to \(-13\) (the coefficient of \(x\)). The numbers are \(-10\) and \(-3\) since \((-10)\times(-3) = 30\) and \((-10)+(-3)=-13\).
Step2: Factor the quadratic
Using the numbers found, we can factor the quadratic as \((x - 10)(x - 3)\) because \(x^{2}-13x + 30=(x-10)(x - 3)\).
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\((x - 10)(x - 3)\)