Question

question
factor completely.
$9y^2 - 1$

Explanation:

Step1: Identify the form

The expression \(9y^2 - 1\) is a difference of squares, since \(9y^2=(3y)^2\) and \(1 = 1^2\). The formula for factoring a difference of squares is \(a^2 - b^2=(a + b)(a - b)\).

Step2: Apply the formula

Here, \(a = 3y\) and \(b = 1\). Substituting these into the formula, we get \((3y + 1)(3y - 1)\).

Answer:

\((3y + 1)(3y - 1)\)