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factor completely.
$1 - 36y^2$
answer attempt 1 out of 2
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Step1: Identify the form
The expression \(1 - 36y^2\) is a difference of squares, which has the form \(a^2 - b^2\), where \(a = 1\) and \(b = 6y\) (since \((6y)^2=36y^2\) and \(1^2 = 1\)).
Step2: Apply difference of squares formula
The formula for factoring a difference of squares is \(a^2 - b^2=(a + b)(a - b)\). Substituting \(a = 1\) and \(b = 6y\) into the formula, we get:
\(1 - 36y^2=(1 + 6y)(1 - 6y)\)
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\((1 + 6y)(1 - 6y)\)