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Question
question
factor the expression completely.
$40x^2 - 48$
Step1: Find the GCF of 40 and 48
The greatest common factor (GCF) of 40 and 48 is 8. So we factor out 8 from the expression.
$$40x^{2}-48 = 8(5x^{2}-6)$$
Step2: Check if \(5x^{2}-6\) can be factored further
The expression \(5x^{2}-6\) is a difference of terms where \(5x^{2}\) is not a perfect square in the context of integer - coefficient factoring (since 5 is not a perfect square and there are no common factors between 5 and 6 other than 1). So the factoring is complete.
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\(8(5x^{2}-6)\)