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question for the following set of data, find the population standard de…

Question

question for the following set of data, find the population standard deviation, to the nearest hundredth. 53, 75, 123, 103, 87, 51, 134 answer attempt 1 out of 2 open statistics calculator copy values for calculator submit answer watch video show examples

Explanation:

Step1: Calculate the mean

The data set is \(53,75,123,103,87,51,134\). The mean \(\bar{x}=\frac{53 + 75+123+103+87+51+134}{7}=\frac{626}{7}\approx89.43\)

Step2: Calculate the squared - differences

\((53 - 89.43)^2=(- 36.43)^2 = 1327.14\)
\((75 - 89.43)^2=(-14.43)^2 = 208.22\)
\((123 - 89.43)^2=(33.57)^2 = 1126.94\)
\((103 - 89.43)^2=(13.57)^2 = 184.14\)
\((87 - 89.43)^2=(-2.43)^2 = 5.9\)
\((51 - 89.43)^2=(-38.43)^2 = 1476.86\)
\((134 - 89.43)^2=(44.57)^2 = 1986.48\)

Step3: Calculate the variance

The variance \(\sigma^{2}=\frac{1327.14 + 208.22+1126.94+184.14+5.9+1476.86+1986.48}{7}=\frac{6315.7}{7}\approx902.24\)

Step4: Calculate the standard deviation

The standard deviation \(\sigma=\sqrt{902.24}\approx30.04\)

Answer:

\(30.04\)