Question

question
go step by step to reduce the radical.
\sqrt{224}
\sqrt{\square} \sqrt{\square}

Explanation:

Step1: Factor 224 into a perfect square and another number

We know that \( 16 \times 14 = 224 \), and \( 16 \) is a perfect square (\( 4^2 = 16 \)). So we can rewrite \( \sqrt{224} \) as \( \sqrt{16 \times 14} \).

Step2: Use the property of square roots \(\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\) (where \(a\geq0\) and \(b\geq0\))

Applying this property to \(\sqrt{16\times14}\), we get \( \sqrt{16} \times \sqrt{14} \).

Answer:

\(\sqrt{16}\) \(\sqrt{14}\) (So the boxes should be filled with 16 and 14 respectively)