Question

question john and his children went into a movie theater and he bought $44.25 worth of drinks and pretzels. each drink costs $5 and each pretzel costs $4.75. he bought twice as many drinks as pretzels. determine the number of drinks and the number of pretzels that john bought. answer attempt 1 out of 2 john bought drinks and pretzels. submit answer

Explanation:

Step1: Define variables

Let \( x \) be the number of pretzels, and \( y \) be the number of drinks. We know that \( y = 2x \) (twice as many drinks as pretzels).

Step2: Set up cost equation

The cost of drinks is \( 5y \) and the cost of pretzels is \( 4.75x \). The total cost is \( 44.25 \), so the equation is \( 5y + 4.75x = 44.25 \).

Step3: Substitute \( y = 2x \) into the equation

Substitute \( y = 2x \) into \( 5y + 4.75x = 44.25 \):
\[

$$\begin{align*} 5(2x) + 4.75x &= 44.25 \\ 10x + 4.75x &= 44.25 \\ 14.75x &= 44.25 \end{align*}$$

\]

Step4: Solve for \( x \)

Divide both sides by \( 14.75 \):
\[
x = \frac{44.25}{14.75} = 3
\]

Step5: Solve for \( y \)

Since \( y = 2x \), substitute \( x = 3 \):
\[
y = 2 \times 3 = 6
\]

Answer:

John bought \( 6 \) drinks and \( 3 \) pretzels.