Question

question
let a and b be mutually exclusive events. if $p(a) = 34\\%$ and $p(b) = 17\\%$, what is $p(a \text{ or } b)$?
provide your answer below:

Explanation:

Step1: Recall the formula for mutually exclusive events

For mutually exclusive events \( A \) and \( B \), the formula for \( P(A \text{ OR } B) \) is \( P(A \text{ OR } B)=P(A) + P(B) \).

Step2: Substitute the given probabilities

We know that \( P(A) = 34\%=0.34 \) and \( P(B)=17\% = 0.17 \). Substituting these values into the formula, we get \( P(A \text{ OR } B)=34\%+ 17\% \).

Step3: Calculate the sum

\( 34\%+17\% = 51\% \).

Answer:

\( 51\% \)