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Question
question 5 (multiple choice worth 2 points) (03.07 mc) in humans, the allele for having dimples is dominant to the allele for not having dimples. what would you expect to see in the offspring of a woman with dimples who is homozygous (dd) and a man who is heterozygous (dd) for the trait? none of their offspring will have dimples. all of their offspring will have dimples. the probability of their offspring having dimples is 50 percent. their offspring will have a 75 percent chance of having dimples.
Step1: Determine parental genotypes
The woman is homozygous (DD) and the man is heterozygous (Dd) for the dimple - trait.
Step2: Set up Punnett - square
The possible gametes from the woman are all D, and from the man are D and d. The Punnett - square has two columns (gametes from the man: D and d) and one row (gamete from the woman: D).
Step3: Calculate genotypes of offspring
The genotypes of the offspring are DD and Dd. The probability of DD is $\frac{1}{2}$ and the probability of Dd is $\frac{1}{2}$. Since both DD and Dd result in having dimples (because D is dominant), the probability of having dimples is 100% or all of their offspring will have dimples.
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C. All of their offspring will have dimples