Question

question 5 of 5 the number of bacteria in a particular petri dish doubles every hour. if the petri dish starts with 1 bacterium, which expression gives the number of bacteria in the petri dish after 5 hours? 1. (2cdot2cdot2cdot2cdot2 = 2^{5}) 2. (1 + 2cdot5) 3. (1+2 + 6+12 + 24) 4. (2 + 4+8 + 16+32)

Explanation:

Step1: Identify growth pattern

The bacteria doubles every hour. Starting with 1 bacterium, after 1 hour there are $1\times2 = 2^1$ bacteria, after 2 hours there are $1\times2\times2=2^2$ bacteria, and so on.

Step2: Calculate after 5 hours

After 5 hours, the number of bacteria is $2\times2\times2\times2\times2 = 2^5$ since it doubles 5 times.

Answer:

1. $2\cdot2\cdot2\cdot2\cdot2 = 2^5$