Question

question 6 (1 point)
(02.05 mc)
neglecting air resistance, how far does an object fall from rest after 3.0 seconds?
○ a 29 m
○ b 44 m
○ c 88 m
○ d 220 m

Explanation:

Step1: Identify the formula

Use the free - fall displacement formula $d = v_0t+\frac{1}{2}gt^2$. Since the object starts from rest, $v_0 = 0$. The acceleration due to gravity $g\approx9.8\ m/s^2$ and $t = 3.0\ s$.

Step2: Substitute values

Substitute $v_0 = 0$, $g = 9.8\ m/s^2$ and $t = 3.0\ s$ into the formula. We get $d=\frac{1}{2}\times9.8\times(3.0)^2$.
First, calculate $(3.0)^2=9$. Then $\frac{1}{2}\times9.8\times9 = 4.9\times9=44.1\ m\approx44\ m$.

Answer:

B. 44 m