Question

question 2 (1 point) a 47.9v battery, a 11ω light bulb and a 8ω resistor are connected in the circuit shown: what is the potential difference across the resistor? type only numbers in the answer box and use standard unit abbreviations for the unit box. your answer: 1 answer units

Explanation:

Step1: Calculate total resistance

$R_{total} = 11\,\Omega + 8\,\Omega = 19\,\Omega$

Step2: Find circuit current

$I = \frac{V}{R_{total}} = \frac{47.9\,\text{V}}{19\,\Omega} = 2.521\,\text{A}$

Step3: Calculate resistor voltage

$V_{resistor} = I \times R_{resistor} = 2.521\,\text{A} \times 8\,\Omega$

Answer:

20.17 V