Question

question 4 (1 point)
if the current flowing through a circuit of constant resistance is doubled, the power dissipated by that circuit will
quadruple.
double.
decrease to one half.
decrease to one fourth.

Explanation:

Step1: Recall the power formula for a circuit

The power \( P \) dissipated in a circuit with resistance \( R \) and current \( I \) is given by the formula \( P = I^2R \). Here, the resistance \( R \) is constant.

Step2: Analyze the change in current

Let the initial current be \( I_1 \) and the initial power be \( P_1 \). So, \( P_1=I_1^2R \). Now, the current is doubled, so the new current \( I_2 = 2I_1 \).

Step3: Calculate the new power

The new power \( P_2 \) with current \( I_2 \) is \( P_2 = I_2^2R=(2I_1)^2R = 4I_1^2R \).

Step4: Compare the new power with the initial power

Since \( P_1 = I_1^2R \), we can see that \( P_2 = 4P_1 \). So when the current is doubled (with constant resistance), the power quadruples.

Answer:

quadruple.