Question

question 9 (1 point)
solve the inequality.
\\(\frac{k}{-3} \geq 7\\)
\\(\circ\\) a \\(k \leq -21\\)
\\(\circ\\) b \\(k \geq -21\\)
\\(\circ\\) c \\(k \geq 10\\)

Explanation:

Step1: Multiply both sides by -3

When multiplying or dividing an inequality by a negative number, the direction of the inequality sign flips. So we have $\frac{k}{-3} \times (-3) \leq 7 \times (-3)$ (note the inequality sign flips from $\geq$ to $\leq$ because we multiplied by -3).

Step2: Simplify both sides

Simplifying the left side gives $k$, and simplifying the right side gives $-21$. So we get $k \leq -21$.

Answer:

a. $k \leq -21$