Question

question 2 (1 point)
what is the slope of the secant line of
$f(x) = x^2 - 2x + 3$
at x=1 and x=3?
your answer:
answer
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Explanation:

Step1: Find $f(1)$

Substitute $x=1$ into $f(x)$:
$f(1) = 1^2 - 2(1) + 3 = 1 - 2 + 3 = 2$

Step2: Find $f(3)$

Substitute $x=3$ into $f(x)$:
$f(3) = 3^2 - 2(3) + 3 = 9 - 6 + 3 = 6$

Step3: Calculate secant slope

Use slope formula $\frac{f(3)-f(1)}{3-1}$:
$\frac{6-2}{3-1} = \frac{4}{2} = 2$

Answer:

2