Question

question 1
1 pts
divide using long division.
$(x^2 + 13x + 42) \div (x + 6)$
$\circ$ $x^2 + 13$
$\circ$ $x + 13$
$\circ$ $x + 7$
$\circ$ $x^2 + 7$
question 2
1 pts

Explanation:

Step1: Divide leading terms

$\frac{x^2}{x}=x$

Step2: Multiply divisor by $x$

$x(x+6)=x^2+6x$

Step3: Subtract from dividend

$(x^2+13x+42)-(x^2+6x)=7x+42$

Step4: Divide new leading terms

$\frac{7x}{x}=7$

Step5: Multiply divisor by $7$

$7(x+6)=7x+42$

Step6: Subtract to find remainder

$(7x+42)-(7x+42)=0$

Step7: Combine quotient terms

$x+7$

Answer:

$\boldsymbol{x+7}$ (Option: $\boldsymbol{x + 7}$)