Question

question 2
1 pts
submarine window: a submarine is submerged 500 meters deep in the ocean. find the hydrostatic pressure exerted on its windows. (sea water density = 1025 kg/m³)
p = pa

Explanation:

Step1: Recall hydrostatic pressure formula

$P =
ho gh$ where $
ho$ is density, $g$ is acceleration due to gravity ($g = 9.8\ m/s^{2}$), and $h$ is depth.

Step2: Substitute given values

$
ho= 1025\ kg/m^{3}$, $g = 9.8\ m/s^{2}$, $h = 500\ m$
$P=1025\times9.8\times500$

Step3: Calculate the pressure

$P = 1025\times9.8\times500=5022500\ Pa$

Answer:

$5022500$