Question

question 1
1 pts
two identical blocks are connected by a spring (of negligible mass), which is stretched from its natural length by a distance 0.25m and the scale reads 34.5n. the mass of the larger block is 7kg. find the spring constant in newtons per meter. provide at least one decimal place

Explanation:

Step1: Calculate weight of large block

Weight $W = mg = 7\mathrm{kg} \times 9.8\mathrm{m/s^2} = 68.6\mathrm{N}$

Step2: Find spring tension force

Tension $F = W - \text{scale reading} = 68.6\mathrm{N} - 34.5\mathrm{N} = 34.1\mathrm{N}$

Step3: Solve for spring constant k

Use Hooke's Law $F = kx$, so $k = \frac{F}{x} = \frac{34.1\mathrm{N}}{0.25\mathrm{m}}$

Answer:

136.4