Question

question 3 1 pts 3. what is the distance between a(-8, 4) and b(4, -1)? a 7 b 10 c 13 d 17

Explanation:

Step1: Recall distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here, $x_1=-8,y_1 = 4,x_2=4,y_2=-1$.

Step2: Calculate differences

$x_2 - x_1=4-(-8)=12$ and $y_2 - y_1=-1 - 4=-5$.

Step3: Square differences and sum

$(x_2 - x_1)^2=12^2 = 144$ and $(y_2 - y_1)^2=(-5)^2 = 25$. Then $(x_2 - x_1)^2+(y_2 - y_1)^2=144 + 25=169$.

Step4: Take square - root

$d=\sqrt{169}=13$.

Answer:

C. 13