Question

question 9
a simple gear train has three gears. the driving gear (a) on the left has
36 teeth. the idler gear (b) has 48 teeth. the driven gear (c) on the
right has 12 teeth. will the driven gear turn faster, slower, or at the
same speed as the driving gear?
faster
slower
at the same speed

Explanation:

Step1: Recall gear speed relationship

For meshed gears, the ratio of rotational speeds is the inverse ratio of their number of teeth: $\frac{n_C}{n_A} = \frac{N_A}{N_C}$, where $n$ is rotational speed, $N$ is number of teeth.

Step2: Substitute given values

$N_A=36$, $N_C=12$. Calculate the speed ratio:
$\frac{n_C}{n_A} = \frac{36}{12} = 3$

Step3: Interpret the ratio

A ratio of 3 means $n_C=3n_A$, so gear C turns 3x faster than A. The idler gear does not change the final speed ratio between driving and driven gears, only direction.

Answer:

Faster