Question

question
simplify the expression completely if possible.
$\frac{x^{2}-9}{x^{2}+x-12}$

Explanation:

Step1: Factor numerator (difference of squares)

$x^2 - 9 = (x+3)(x-3)$

Step2: Factor denominator (quadratic trinomial)

$x^2 + x - 12 = (x+4)(x-3)$

Step3: Cancel common factor

$\frac{(x+3)(x-3)}{(x+4)(x-3)} = \frac{x+3}{x+4}$ (where $x
eq 3, -4$)

Answer:

$\frac{x+3}{x+4}$ (with the restriction $x
eq 3, -4$)