Question

question
use multiplication to expand the expression below. then compute and/or simplify.
$(-2az)^5$
answer attempt 1 out of 2
press the \cdot button or type the * symbol on your keyboard to represent multiplication. using \times for multiplication is inappropriate when x may be used as a variable. for the answer, type the base, then use the $a^b$ button or type the ^ symbol for an exponent.
expanded form:
answer:
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Explanation:

Step1: Recall the power of a product rule

The power of a product rule states that \((xy)^n = x^n y^n\). For \((-2az)^5\), we apply this rule to each factor inside the parentheses.
So, \((-2az)^5 = (-2)^5 \times a^5 \times z^5\)

Step2: Calculate \((-2)^5\)

\((-2)^5 = (-2) \times (-2) \times (-2) \times (-2) \times (-2)\)
Multiplying the numbers: \((-2) \times (-2) = 4\), \(4 \times (-2) = -8\), \(-8 \times (-2) = 16\), \(16 \times (-2) = -32\)
So, \((-2)^5 = -32\)

Step3: Combine the results

Substituting \((-2)^5 = -32\) back into the expression from Step1, we get:
\((-2az)^5 = -32 \times a^5 \times z^5 = -32a^5z^5\)

For the expanded form (showing the multiplication of the base 5 times):
\((-2az)^5 = (-2az) \times (-2az) \times (-2az) \times (-2az) \times (-2az)\)

Answer:

(Expanded Form):
\((-2az) \times (-2az) \times (-2az) \times (-2az) \times (-2az)\)