Question

question what is the area, in square inches, of the isosceles trapezoid below? answer attempt 1 out of 2 a = in²

Explanation:

Step1: Recall area formula for trapezoid

The formula for the area of a trapezoid is $A=\frac{(b_1 + b_2)h}{2}$, where $b_1$ and $b_2$ are the lengths of the parallel - sides and $h$ is the height.

Step2: Identify values of $b_1$, $b_2$ and $h$

Here, $b_1 = 18.5$ in, $b_2=8.5$ in and $h = 5.7$ in.

Step3: Substitute values into formula

$A=\frac{(18.5 + 8.5)\times5.7}{2}=\frac{27\times5.7}{2}$.

Step4: Calculate the result

$27\times5.7 = 153.9$, then $\frac{153.9}{2}=76.95$ in².

Answer:

$76.95$