Question

question
what is the product of $2\sqrt{8}$ and $6\sqrt{12}$ in simplest radical form?
answer
attempt 1 out of 2
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Explanation:

Step1: Multiply coefficients and radicands

$(2 \times 6) \times \sqrt{8 \times 12}$
$=12 \times \sqrt{96}$

Step2: Simplify the radical

Factor 96 into perfect square and remainder: $\sqrt{16 \times 6} = \sqrt{16} \times \sqrt{6} = 4\sqrt{6}$

Step3: Multiply by the coefficient

$12 \times 4\sqrt{6}$
$=48\sqrt{6}$

Answer:

$48\sqrt{6}$