Question

question 3
what is the solution set of the inequality 3x + 4 > 10 and 2x - 5 ≤ 7? (fill each blank with an integer.)
□ < x ≤ □

Explanation:

Step1: Solve first inequality

$3x + 4 > 10$
Subtract 4 from both sides:
$3x > 10 - 4$
$3x > 6$
Divide by 3:
$x > 2$

Step2: Solve second inequality

$3x - 5 \leq 7$
Add 5 to both sides:
$3x \leq 7 + 5$
$3x \leq 12$
Divide by 3:
$x \leq 4$

Step3: Combine solutions

The overlap of $x > 2$ and $x \leq 4$ is $2 < x \leq 4$

Answer:

$2 < x \leq 4$