Question

a radiographic technique chart recommends 4 milliampere - seconds (mas) and 68 kilovoltage peak (kvp) at 72 inches for a certain procedure. how will the receptor exposure be affected if the radiograph is performed using the recommended exposure technique but at 60 inches? receptor exposure will not be affected receptor exposure will be lower than desired receptor exposure will be higher than necessary

Explanation:

Step1: Recall the inverse - square law

The intensity of the x - ray beam (and thus receptor exposure) is inversely proportional to the square of the distance from the source. The formula is $I_1d_1^{2}=I_2d_2^{2}$, where $I$ is the intensity of the x - ray beam and $d$ is the distance.

Step2: Compare the distances

The recommended distance $d_1 = 72$ inches and the new distance $d_2=60$ inches. Since $d_2

Answer:

Receptor exposure will be higher than necessary