Question

a rectangle has an area of 40 square units. the length is 6 units greater than the width. what are the dimensions of the rectangle? 13 by 7 8 by 5 10 by 4 11 by 9

Explanation:

Step1: Define variables for width/length

Let width = $w$, length = $w+6$

Step2: Set up area equation

Area: $w(w+6)=40$
Expand: $w^2+6w-40=0$

Step3: Solve quadratic equation

Factor: $(w+10)(w-4)=0$
Solutions: $w=4$ (discard $w=-10$)

Step4: Calculate length

Length = $4+6=10$

Answer:

10 by 4