Question

a rectangles length is 5 inches more than twice its width. its area is 50 square inches. which equation can be used to find its width, w? 2w(2w + 5) = 50 2w(w + 5) = 50 w(2w + 5) = 50 w(w + 5) = 50

Explanation:

Step1: Define length in terms of width

Let width be $w$. Length is 5 inches more than twice the width, so length $l = 2w+5$.

Step2: Use area formula

Area of rectangle $A=l\times w$. Given $A = 50$, substitute $l = 2w + 5$ and $A=50$ into formula: $w(2w + 5)=50$.

Answer:

C. $w(2w + 5)=50$