Question

reflect hijk over the x - axis, then that image over the y - axis. label the coordinates of h.

Explanation:

Step1: Reflection over x - axis rule

The rule for reflecting a point $(x,y)$ over the $x$-axis is $(x,-y)$. Let the coordinates of point $H$ be $(x_1,y_1)$. After reflecting $H$ over the $x$-axis, the new - point $H'$ has coordinates $(x_1, - y_1)$.

Step2: Reflection over y - axis rule

The rule for reflecting a point $(x,y)$ over the $y$-axis is $(-x,y)$. After reflecting $H'=(x_1,-y_1)$ over the $y$-axis, the new - point $H''$ has coordinates $(-x_1,-y_1)$.
Assume the coordinates of point $H$ are $(a,b)$.

1. Reflection over the $x$-axis: The image $H'$ has coordinates $(a, - b)$.
2. Reflection of $H'$ over the $y$-axis: The final image $H''$ has coordinates $(-a,-b)$.

Suppose the coordinates of point $H$ in the given figure are $(3, - 2)$.

1. Reflecting over the $x$-axis: $H'=(3,2)$.
2. Reflecting $H'$ over the $y$-axis: $H''=(-3,2)$.

Answer:

If the original coordinates of $H$ are $(x,y)$, the coordinates of $H''$ are $(-x,-y)$. Without knowing the specific coordinates of $H$ in the figure, the general form of the coordinates of $H''$ after the two - step reflection (first over $x$-axis then over $y$-axis) is $(-x,-y)$. If we assume the coordinates of $H$ are $(3,-2)$ as an example, the coordinates of $H''$ are $(-3,2)$.