Question

1. reflect the square over the line y = -x

a(-1, 3), b(0,6), c(3, 5), d(2,2)

1. reflect the triangle over the line y = -x.

a (-3, 2), b(4, -5), c(2, 0)

Explanation:

Step1: Recall reflection rule

When reflecting a point $(x,y)$ over the line $y = -x$, the new - point $(x',y')$ has coordinates $x'=-y$ and $y'=-x$.

Step2: Reflect point A of the square

For point $A(-1,3)$, using the rule $x'=-y$ and $y'=-x$, we have $x'=-3$ and $y' = 1$. So $A'(-3,1)$.

Step3: Reflect point B of the square

For point $B(0,6)$, $x'=-6$ and $y' = 0$. So $B'(-6,0)$.

Step4: Reflect point C of the square

For point $C(3,5)$, $x'=-5$ and $y'=-3$. So $C'(-5,-3)$.

Step5: Reflect point D of the square

For point $D(2,2)$, $x'=-2$ and $y'=-2$. So $D'(-2,-2)$.

Step6: Reflect point A of the triangle

For point $A(-3,2)$ of the triangle, $x'=-2$ and $y' = 3$. So $A'(-2,3)$.

Step7: Reflect point B of the triangle

For point $B(4,-5)$ of the triangle, $x' = 5$ and $y'=-4$. So $B'(5,-4)$.

Step8: Reflect point C of the triangle

For point $C(2,0)$ of the triangle, $x'=0$ and $y'=-2$. So $C'(0,-2)$.

Answer:

$A'(-3,1)$
$B'(-6,0)$
$C'(-5,-3)$
$D'(-2,-2)$
$A'(-2,3)$
$B'(5,-4)$
$C'(0,-2)$