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Question
a reflection across \\(\overline{qr}\\) followed by a rotation \\(180^\circ\\) about point \\(q\\) maps equilateral triangle \\(qrs\\) onto triangle \\(qrs\\).
select all of the true statements.
- the position of point \\(q\\) is the same as the position of point \\(q\\).
- \\(\triangle qrs \cong \triangle qrs\\)
- \\(\overline{qr} \cong \overline{rs} \cong \overline{sq}\\)
- the position of point \\(r\\) is the same as the position of point \\(r\\).
Brief Explanations
- Point Q's position: A reflection across $\overline{QR}$ leaves Q unchanged, and a 180° rotation about Q also leaves Q in place. So Q and Q' coincide.
- Triangle congruence: Reflections and rotations are rigid transformations, which preserve size and shape, so $\triangle QRS \cong \triangle Q'R'S'$.
- Side congruence: Since $\triangle QRS$ is equilateral, all sides are equal. Rigid transformations preserve side lengths, so $\overline{Q'R'} \cong \overline{R'S'} \cong \overline{S'Q'}$.
- Point R's position: Reflecting R across $\overline{QR}$ leaves R unchanged, but a 180° rotation about Q moves R to a new position, so R and R' do not coincide.
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- The position of point Q is the same as the position of point Q'.
- $\triangle QRS \cong \triangle Q'R'S'$
- $\overline{Q'R'} \cong \overline{R'S'} \cong \overline{S'Q'}$