Question

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relaciona el ancho con el área y longitud dada de un rectángulo.
$w = 6.5\text{ cm}$ $w = 8.8\text{ cm}$ $w = 6\text{ cm}$ $w = 6.25\text{ cm}$
$l = 5\text{ cm};a = 31.25\text{ cm}^2$
$l = 7.5\text{ cm};a = 48.75\text{ cm}^2$
$l = 9.25\text{ cm};a = 55.5\text{ cm}^2$
$l = 5\text{ cm};a = 44\text{ cm}^2$

Explanation:

Step1: Recall rectangle area formula

The area formula of a rectangle is $A = l\times w$, where $A$ is the area, $l$ is the length and $w$ is the width. We can solve for $w$ as $w=\frac{A}{l}$.

Step2: Calculate width for $l = 5\mathrm{cm},A = 31.25\mathrm{cm}^2$

$w=\frac{31.25}{5}=6.25\mathrm{cm}$

Step3: Calculate width for $l = 7.5\mathrm{cm},A = 48.75\mathrm{cm}^2$

$w=\frac{48.75}{7.5}=6.5\mathrm{cm}$

Step4: Calculate width for $l = 9.25\mathrm{cm},A = 55.5\mathrm{cm}^2$

$w=\frac{55.5}{9.25}=6\mathrm{cm}$

Step5: Calculate width for $l = 5\mathrm{cm},A = 44\mathrm{cm}^2$

$w=\frac{44}{5}=8.8\mathrm{cm}$

Answer:

$l = 5\mathrm{cm},A = 31.25\mathrm{cm}^2$ corresponds to $w = 6.25\mathrm{cm}$
$l = 7.5\mathrm{cm},A = 48.75\mathrm{cm}^2$ corresponds to $w = 6.5\mathrm{cm}$
$l = 9.25\mathrm{cm},A = 55.5\mathrm{cm}^2$ corresponds to $w = 6\mathrm{cm}$
$l = 5\mathrm{cm},A = 44\mathrm{cm}^2$ corresponds to $w = 8.8\mathrm{cm}$