Question

remember
for problems 12–15, solve for x.

1. \\(\frac{1}{3}x + 6 = 4\\)
2. \\(\frac{1}{3}x + 7 = -7\\)

Explanation:

Step1: Subtract 6 from both sides

$\frac{1}{3}x + 6 - 6 = 4 - 6$
$\frac{1}{3}x = -2$

Step2: Multiply by 3 on both sides

$\frac{1}{3}x \times 3 = -2 \times 3$
$x = -6$

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Step1: Subtract 7 from both sides

$\frac{1}{3}x + 7 - 7 = -7 - 7$
$\frac{1}{3}x = -14$

Step2: Multiply by 3 on both sides

$\frac{1}{3}x \times 3 = -14 \times 3$
$x = -42$

Answer:

For problem 12: $x = -6$
For problem 14: $x = -42$