Question

rewrite polynomials in standard form
score: 2/30 penalty: 1 off
question
rewrite the following polynomial in standard form.
\\(-7x^3 - 1 - \frac{1}{9}x\\)
answer attempt 1 out of 2
answer:
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Explanation:

Step1: Recall standard form of polynomial

Standard form of a polynomial is arranging terms in descending order of exponents. The general form for a cubic polynomial is $ax^3 + bx^2 + cx + d$ (where $b = 0$ here as there is no $x^2$ term).
Given polynomial: $-7x^3 - 1 - \frac{1}{9}x$

Step2: Rearrange terms by degree

The term with $x^3$ is $-7x^3$, the term with $x$ is $-\frac{1}{9}x$, and the constant term is $-1$.
So arranging in descending order of exponents (from highest degree to lowest, then constant), we get:
$-7x^3 - \frac{1}{9}x - 1$

Answer:

$-7x^3 - \frac{1}{9}x - 1$